What are the solutions to the equation n^2=20-n ?

The solutions to the equation n^2=20-n are n=4,n=-5

Find the zeros of n^2=20-n

The zeros of n^2=20-n are n=4,n=-5

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n^{2} = 20 - n

n = 4, n = - 5

Solution steps

n^{2} = 20 - n

Move

n

to the left side

n^{2} + n = 20

Move

20

to the left side

n^{2} + n - 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 20) = 9

n_{1, 2} = \frac{- 1 \pm 9}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 1 + 9}{2 \cdot 1}, n_{2} = \frac{- 1 - 9}{2 \cdot 1}

n = \frac{- 1 + 9}{2 \cdot 1} : 4

n = \frac{- 1 - 9}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

n = 4, n = - 5

x, x^{2} + p x + 12 = 0

x^{2} - \frac{81}{4} = 0

t, - \frac{1}{2} \cdot g \cdot t^{2} + v \cdot t = 0

x^{2} - 12 x + 36 = x

2 x^{2} - 12 x + 14

What are the solutions to the equation n^2=20-n ?
The solutions to the equation n^2=20-n are n=4,n=-5
Find the zeros of n^2=20-n
The zeros of n^2=20-n are n=4,n=-5