What are the solutions to the equation factor 2x^2+6x-8=0 ?

The solutions to the equation factor 2x^2+6x-8=0 are x=1,x=-4

Find the zeros of factor 2x^2+6x-8=0

The zeros of factor 2x^2+6x-8=0 are x=1,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + 6 x - 8 = 0

x = 1, x = - 4

Solution steps

2 x^{2} + 6 x - 8 = 0

Factor

2 x^{2} + 6 x - 8 : 2 (x - 1) (x + 4)

2 (x - 1) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or x + 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = 1, x = - 4

1 - x = 30 x^{2}

- 2 x^{2} - 7 x - 6 = 0

x^{2} + 6 x + 9 = 0

m^{2} + 10 = 1

x, x^{2} + y^{2} - 4 x y = 0

What are the solutions to the equation factor 2x^2+6x-8=0 ?
The solutions to the equation factor 2x^2+6x-8=0 are x=1,x=-4
Find the zeros of factor 2x^2+6x-8=0
The zeros of factor 2x^2+6x-8=0 are x=1,x=-4