What is factor m^2+4m+3 ?

The solution to factor m^2+4m+3 is (m+1)(m+3)

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factor m^2+4m+3

factor

m^{2} + 4 m + 3

(m + 1) (m + 3)

Solution steps

m^{2} + 4 m + 3

Break the expression into groups

= (m^{2} + m) + (3 m + 3)

Factor out

m

from

m^{2} + m : m (m + 1)

Factor out

3

from

3 m + 3 : 3 (m + 1)

= m (m + 1) + 3 (m + 1)

Factor out common term

m + 1

= (m + 1) (m + 3)

(\frac{- 7 a ^{2} b ^{3} c ^{0}}{3 a ^{3} b ^{4} c ^{3}})^{- 4}

- 4.5 < x

3 x + 2 = 5 x - 8

2 - 49

- 5 (- 3 x + 2) = 95