What are the solutions to the equation s^2+2s+6=0 ?

The solutions to the equation s^2+2s+6=0 are s=-1+sqrt(5)i,s=-1-sqrt(5)i

Find the zeros of s^2+2s+6=0

The zeros of s^2+2s+6=0 are s=-1+sqrt(5)i,s=-1-sqrt(5)i

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s^{2} + 2 s + 6 = 0

s = - 1 + 5 i, s = - 1 - 5 i

Solution steps

s^{2} + 2 s + 6 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 6 : 25 i

s_{1, 2} = \frac{- 2 \pm 2 5 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 5 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 5 i}{2 \cdot 1}

s = \frac{- 2 + 2 5 i}{2 \cdot 1} : - 1 + 5 i

s = \frac{- 2 - 2 5 i}{2 \cdot 1} : - 1 - 5 i

The solutions to the quadratic equation are:

s = - 1 + 5 i, s = - 1 - 5 i

x^{2} + 8 x - 1 = 0

6 x^{2} = - 7 x + 20

1640.8 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

5 y^{2} - 45 = 0

10 x^{2} = 18 x

What are the solutions to the equation s^2+2s+6=0 ?
The solutions to the equation s^2+2s+6=0 are s=-1+sqrt(5)i,s=-1-sqrt(5)i
Find the zeros of s^2+2s+6=0
The zeros of s^2+2s+6=0 are s=-1+sqrt(5)i,s=-1-sqrt(5)i