What are the solutions to the equation 6x^2-x^2+2x=x ?

The solutions to the equation 6x^2-x^2+2x=x are x=0,x=-1/5

Find the zeros of 6x^2-x^2+2x=x

The zeros of 6x^2-x^2+2x=x are x=0,x=-1/5

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6 x^{2} - x^{2} + 2 x = x

x = 0, x = - \frac{1}{5}

Decimal Notation

x = 0, x = - 0.2

Solution steps

6 x^{2} - x^{2} + 2 x = x

Refine

5 x^{2} + 2 x = x

Move

x

to the left side

5 x^{2} + x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

1^{2} - 4 \cdot 5 \cdot 0 = 1

x_{1, 2} = \frac{- 1 \pm 1}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 1}{2 \cdot 5}, x_{2} = \frac{- 1 - 1}{2 \cdot 5}

x = \frac{- 1 + 1}{2 \cdot 5} : 0

x = \frac{- 1 - 1}{2 \cdot 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 0, x = - \frac{1}{5}

P^{2} = 2.97370166 \cdot 1 0^{- 19} \cdot 149597870700 0^{3}

x, (f \circ g) (x) = 3 x^{2} + 1

1 5^{2} + 1 4^{2} = x^{2}

x^{2} - 4 x = - x

5 x^{2} = 50

What are the solutions to the equation 6x^2-x^2+2x=x ?
The solutions to the equation 6x^2-x^2+2x=x are x=0,x=-1/5
Find the zeros of 6x^2-x^2+2x=x
The zeros of 6x^2-x^2+2x=x are x=0,x=-1/5