What are the solutions to the equation (x^2)(3)=114 ?

The solutions to the equation (x^2)(3)=114 are x=sqrt(38),x=-sqrt(38)

Find the zeros of (x^2)(3)=114

The zeros of (x^2)(3)=114 are x=sqrt(38),x=-sqrt(38)

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(x^{2}) (3) = 114

x = 38, x = - 38

Decimal Notation

x = 6.16441 \dots, x = - 6.16441 \dots

Solution steps

(x^{2}) (3) = 114

Divide both sides by

3

x^{2} = 38

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 38, x = - 38

- 4.91 (\frac{10 982}{491} - x)^{2} + 1.6 = 0

2 u^{2} + 4 u + 9 = (u - 1)^{2}

- 6 x^{2} + 66 x - 60 = 0

4.9 t^{2} + 20 t - 200 = 0

- 2 x = (x + 1)^{2} + 2

What are the solutions to the equation (x^2)(3)=114 ?
The solutions to the equation (x^2)(3)=114 are x=sqrt(38),x=-sqrt(38)
Find the zeros of (x^2)(3)=114
The zeros of (x^2)(3)=114 are x=sqrt(38),x=-sqrt(38)