What are the solutions to the equation 4(x+5)^2-7(x+2)^2=6x ?

The solutions to the equation 4(x+5)^2-7(x+2)^2=6x are x=-4,x=6

Find the zeros of 4(x+5)^2-7(x+2)^2=6x

The zeros of 4(x+5)^2-7(x+2)^2=6x are x=-4,x=6

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4 (x + 5)^{2} - 7 (x + 2)^{2} = 6 x

x = - 4, x = 6

Solution steps

4 (x + 5)^{2} - 7 (x + 2)^{2} = 6 x

Expand

4 (x + 5)^{2} - 7 (x + 2)^{2} : - 3 x^{2} + 12 x + 72

- 3 x^{2} + 12 x + 72 = 6 x

Move

6 x

to the left side

- 3 x^{2} + 6 x + 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) \cdot 72}{2 ( - 3 )}

6^{2} - 4 (- 3) \cdot 72 = 30

x_{1, 2} = \frac{- 6 \pm 30}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 6 + 30}{2 ( - 3 )}, x_{2} = \frac{- 6 - 30}{2 ( - 3 )}

x = \frac{- 6 + 30}{2 ( - 3 )} : - 4

x = \frac{- 6 - 30}{2 ( - 3 )} : 6

The solutions to the quadratic equation are:

x = - 4, x = 6

- 4 k^{2} - 8 k - 3 = - 3 - 5 k^{2}

x^{2} + 3 x - 1 = - x + 4

0 = - 16 t^{2} + 128 t + 144

x^{2} + 6 x + 73

- 150 = 90 t - 4.9 t^{2}

What are the solutions to the equation 4(x+5)^2-7(x+2)^2=6x ?
The solutions to the equation 4(x+5)^2-7(x+2)^2=6x are x=-4,x=6
Find the zeros of 4(x+5)^2-7(x+2)^2=6x
The zeros of 4(x+5)^2-7(x+2)^2=6x are x=-4,x=6