What are the solutions to the equation x^2+sqrt(5)x-19=0 ?

The solutions to the equation x^2+sqrt(5)x-19=0 are x=(-sqrt(5)+9)/2 ,x=(-sqrt(5)-9)/2

Find the zeros of x^2+sqrt(5)x-19=0

The zeros of x^2+sqrt(5)x-19=0 are x=(-sqrt(5)+9)/2 ,x=(-sqrt(5)-9)/2

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x^{2} + 5 x - 19 = 0

x = \frac{- 5 + 9}{2}, x = \frac{- 5 - 9}{2}

Decimal Notation

x = 3.38196 \dots, x = - 5.61803 \dots

Solution steps

x^{2} + 5 x - 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm ( 5 ) ^{2} - 4 \cdot 1 \cdot ( - 19 )}{2 \cdot 1}

(5)^{2} - 4 \cdot 1 \cdot (- 19) = 9

x_{1, 2} = \frac{- 5 \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 9}{2 \cdot 1}, x_{2} = \frac{- 5 - 9}{2 \cdot 1}

x = \frac{- 5 + 9}{2 \cdot 1} : \frac{- 5 + 9}{2}

x = \frac{- 5 - 9}{2 \cdot 1} : \frac{- 5 - 9}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 9}{2}, x = \frac{- 5 - 9}{2}

4 x^{2} - 7 x + 9 = 0

- 2 (x - 4)^{2} + 50 = 0

x, y^{2} = x^{2} + z^{2}

2 x - x^{2} + 3 = 0

8 + 4 z - z^{2} = 0

What are the solutions to the equation x^2+sqrt(5)x-19=0 ?
The solutions to the equation x^2+sqrt(5)x-19=0 are x=(-sqrt(5)+9)/2 ,x=(-sqrt(5)-9)/2
Find the zeros of x^2+sqrt(5)x-19=0
The zeros of x^2+sqrt(5)x-19=0 are x=(-sqrt(5)+9)/2 ,x=(-sqrt(5)-9)/2