What are the solutions to the equation 2x^2-7=7(x-1)+2x ?

The solutions to the equation 2x^2-7=7(x-1)+2x are x= 9/2 ,x=0

Find the zeros of 2x^2-7=7(x-1)+2x

The zeros of 2x^2-7=7(x-1)+2x are x= 9/2 ,x=0

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2 x^{2} - 7 = 7 (x - 1) + 2 x

x = \frac{9}{2}, x = 0

Decimal Notation

x = 4.5, x = 0

Solution steps

2 x^{2} - 7 = 7 (x - 1) + 2 x

Expand

7 (x - 1) + 2 x : 9 x - 7

2 x^{2} - 7 = 9 x - 7

Move

7

to the left side

2 x^{2} = 9 x

Move

9 x

to the left side

2 x^{2} - 9 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 2 \cdot 0}{2 \cdot 2}

(- 9)^{2} - 4 \cdot 2 \cdot 0 = 9

x_{1, 2} = \frac{- ( - 9 ) \pm 9}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 9}{2 \cdot 2}, x_{2} = \frac{- ( - 9 ) - 9}{2 \cdot 2}

x = \frac{- ( - 9 ) + 9}{2 \cdot 2} : \frac{9}{2}

x = \frac{- ( - 9 ) - 9}{2 \cdot 2} : 0

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = 0

5 x + 3 = 4 x^{2}

x, 36 x^{2} + 16 y^{2} - 9 z^{2} - 144 = 0

3 x^{2} - 160 x + 1600 = 0

\frac{309}{16} xx + \frac{43}{12} = \frac{73}{12}

- 3 y^{2} + 90 y - 600 = 0

What are the solutions to the equation 2x^2-7=7(x-1)+2x ?
The solutions to the equation 2x^2-7=7(x-1)+2x are x= 9/2 ,x=0
Find the zeros of 2x^2-7=7(x-1)+2x
The zeros of 2x^2-7=7(x-1)+2x are x= 9/2 ,x=0