What are the solutions to the equation 12x^2-196x+468=0 ?

The solutions to the equation 12x^2-196x+468=0 are x=(49+sqrt(997))/6 ,x=(49-sqrt(997))/6

Find the zeros of 12x^2-196x+468=0

The zeros of 12x^2-196x+468=0 are x=(49+sqrt(997))/6 ,x=(49-sqrt(997))/6

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12 x^{2} - 196 x + 468 = 0

x = \frac{49 + 997}{6}, x = \frac{49 - 997}{6}

Decimal Notation

x = 13.42921 \dots, x = 2.90411 \dots

Solution steps

12 x^{2} - 196 x + 468 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 196 ) \pm ( - 196 ) ^{2} - 4 \cdot 12 \cdot 468}{2 \cdot 12}

(- 196)^{2} - 4 \cdot 12 \cdot 468 = 4997

x_{1, 2} = \frac{- ( - 196 ) \pm 4 997}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 196 ) + 4 997}{2 \cdot 12}, x_{2} = \frac{- ( - 196 ) - 4 997}{2 \cdot 12}

x = \frac{- ( - 196 ) + 4 997}{2 \cdot 12} : \frac{49 + 997}{6}

x = \frac{- ( - 196 ) - 4 997}{2 \cdot 12} : \frac{49 - 997}{6}

The solutions to the quadratic equation are:

x = \frac{49 + 997}{6}, x = \frac{49 - 997}{6}

x, x^{2} + 2 y^{2} - 2 x + 8 + 5 = 0

x^{2} = \frac{4}{81}

x, z^{2} = 4 - x^{2} - y^{2}

2 x^{2} - 12 x + (a + 2) = 0

2 x^{2} - 1 x = 0

What are the solutions to the equation 12x^2-196x+468=0 ?
The solutions to the equation 12x^2-196x+468=0 are x=(49+sqrt(997))/6 ,x=(49-sqrt(997))/6
Find the zeros of 12x^2-196x+468=0
The zeros of 12x^2-196x+468=0 are x=(49+sqrt(997))/6 ,x=(49-sqrt(997))/6