What are the solutions to the equation x^2+1=48 ?

The solutions to the equation x^2+1=48 are x=sqrt(47),x=-sqrt(47)

Find the zeros of x^2+1=48

The zeros of x^2+1=48 are x=sqrt(47),x=-sqrt(47)

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x^{2} + 1 = 48

x = 47, x = - 47

Decimal Notation

x = 6.85565 \dots, x = - 6.85565 \dots

Solution steps

x^{2} + 1 = 48

Move

1

to the right side

x^{2} = 47

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 47, x = - 47

x^{2} + 4 x - 42 = 3

x^{2} - 14 = - 10

- x^{2} + 169 x - 28 = 0

x, \frac{x}{y} = \frac{x ^{2}}{y ^{2}}

6 x - 1 \cdot 6 x \cdot 6 x + 2 = 11296

What are the solutions to the equation x^2+1=48 ?
The solutions to the equation x^2+1=48 are x=sqrt(47),x=-sqrt(47)
Find the zeros of x^2+1=48
The zeros of x^2+1=48 are x=sqrt(47),x=-sqrt(47)