What are the solutions to the equation t^2-t-6=-6 ?

The solutions to the equation t^2-t-6=-6 are t=1,t=0

Find the zeros of t^2-t-6=-6

The zeros of t^2-t-6=-6 are t=1,t=0

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t^{2} - t - 6 = - 6

t = 1, t = 0

Solution steps

t^{2} - t - 6 = - 6

Move

6

to the left side

t^{2} - t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

t_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, t_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

t = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

t = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

t = 1, t = 0

t, \frac{b ^{2}}{2} - \frac{t ^{2}}{8} = 1

0 = 4 x - x^{2} - x^{2}

20.13 = - 4.9 t^{2} + 15.3 t + 28.32

x, f = 4 x^{2} - 5 f (5)

3 x^{2} - 5 = x^{2} + 13

What are the solutions to the equation t^2-t-6=-6 ?
The solutions to the equation t^2-t-6=-6 are t=1,t=0
Find the zeros of t^2-t-6=-6
The zeros of t^2-t-6=-6 are t=1,t=0