What are the solutions to the equation (-1-x)(3-x)=0 ?

The solutions to the equation (-1-x)(3-x)=0 are x=-1,x=3

Find the zeros of (-1-x)(3-x)=0

The zeros of (-1-x)(3-x)=0 are x=-1,x=3

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(- 1 - x) (3 - x) = 0

x = - 1, x = 3

Solution steps

(- 1 - x) (3 - x) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

- 1 - x = 0 or 3 - x = 0

Solve

- 1 - x = 0 : x = - 1

Solve

3 - x = 0 : x = 3

The solutions to the quadratic equation are:

x = - 1, x = 3

2 s^{2} + 4 s + 2 = 0

3 c^{2} - 2 c - 4 = \frac{( - 1 ) - ( - 1 )}{( 2 ) - ( - 2 )}

3 x^{2} + 18 x + 15 = 0

x, x^{2} - 6 x + 1 = 0

- 16 x^{2} + 35 = 0

What are the solutions to the equation (-1-x)(3-x)=0 ?
The solutions to the equation (-1-x)(3-x)=0 are x=-1,x=3
Find the zeros of (-1-x)(3-x)=0
The zeros of (-1-x)(3-x)=0 are x=-1,x=3