What are the solutions to the equation solvefor x,y^2+x^2=r^2 ?

The solutions to the equation solvefor x,y^2+x^2=r^2 are x=sqrt(r^2-y^2),x=-sqrt(r^2-y^2)

Find the zeros of solvefor x,y^2+x^2=r^2

The zeros of solvefor x,y^2+x^2=r^2 are x=sqrt(r^2-y^2),x=-sqrt(r^2-y^2)

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solve for

x, y^{2} + x^{2} = r^{2}

x = r^{2} - y^{2}, x = - r^{2} - y^{2}

Solution steps

y^{2} + x^{2} = r^{2}

Move

y^{2}

to the right side

x^{2} = r^{2} - y^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = r^{2} - y^{2}, x = - r^{2} - y^{2}

\frac{7}{3} x + \frac{7}{3} = x^{2} + \frac{4}{3} x + \frac{1}{3}

8 x^{2} + 2 = 0

- x^{2} - 6.6 \cdot 1 0^{- 5} x + 6.6 \cdot 1 0^{- 5} = 0

(x - 4) (x + 3) = 8

t, h = \frac{g \cdot t ^{2}}{2}

What are the solutions to the equation solvefor x,y^2+x^2=r^2 ?
The solutions to the equation solvefor x,y^2+x^2=r^2 are x=sqrt(r^2-y^2),x=-sqrt(r^2-y^2)
Find the zeros of solvefor x,y^2+x^2=r^2
The zeros of solvefor x,y^2+x^2=r^2 are x=sqrt(r^2-y^2),x=-sqrt(r^2-y^2)