What are the solutions to the equation 14^2=7^2+x^2 ?

The solutions to the equation 14^2=7^2+x^2 are x=7sqrt(3),x=-7sqrt(3)

Find the zeros of 14^2=7^2+x^2

The zeros of 14^2=7^2+x^2 are x=7sqrt(3),x=-7sqrt(3)

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1 4^{2} = 7^{2} + x^{2}

x = 73, x = - 73

Decimal Notation

x = 12.12435 \dots, x = - 12.12435 \dots

Solution steps

1 4^{2} = 7^{2} + x^{2}

Switch sides

7^{2} + x^{2} = 1 4^{2}

Move

7^{2}

to the right side

x^{2} = 147

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 147, x = - 147

147 = 73

- 147 = - 73

x = 73, x = - 73

\frac{1}{2} x^{2} + 2 x + 4 = 0

21 - 4 x = x^{2}

5 x^{2} - 3 x = 14

12 x^{2} - 76 x + 90 = 0

λ^{2} - 4 λ + 16 (1) = 0

What are the solutions to the equation 14^2=7^2+x^2 ?
The solutions to the equation 14^2=7^2+x^2 are x=7sqrt(3),x=-7sqrt(3)
Find the zeros of 14^2=7^2+x^2
The zeros of 14^2=7^2+x^2 are x=7sqrt(3),x=-7sqrt(3)