What are the solutions to the equation 1/3 h^2+2/9 h=-5/18 h-7/3 h^2 ?

The solutions to the equation 1/3 h^2+2/9 h=-5/18 h-7/3 h^2 are h=0,h=-3/16

Find the zeros of 1/3 h^2+2/9 h=-5/18 h-7/3 h^2

The zeros of 1/3 h^2+2/9 h=-5/18 h-7/3 h^2 are h=0,h=-3/16

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\frac{1}{3} h^{2} + \frac{2}{9} h = - \frac{5}{18} h - \frac{7}{3} h^{2}

h = 0, h = - \frac{3}{16}

Decimal Notation

h = 0, h = - 0.1875

Solution steps

\frac{1}{3} h^{2} + \frac{2}{9} h = - \frac{5}{18} h - \frac{7}{3} h^{2}

Find Least Common Multiplier of

3, 9, 18 : 18

Multiply by LCM=

18

\frac{1}{3} h^{2} \cdot 18 + \frac{2}{9} h \cdot 18 = - \frac{5}{18} h \cdot 18 - \frac{7}{3} h^{2} \cdot 18

Simplify

6 h^{2} + 4 h = - 5 h - 42 h^{2}

Move

42 h^{2}

to the left side

48 h^{2} + 4 h = - 5 h

Move

5 h

to the left side

48 h^{2} + 9 h = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 48 \cdot 0}{2 \cdot 48}

9^{2} - 4 \cdot 48 \cdot 0 = 9

h_{1, 2} = \frac{- 9 \pm 9}{2 \cdot 48}

Separate the solutions

h_{1} = \frac{- 9 + 9}{2 \cdot 48}, h_{2} = \frac{- 9 - 9}{2 \cdot 48}

h = \frac{- 9 + 9}{2 \cdot 48} : 0

h = \frac{- 9 - 9}{2 \cdot 48} : - \frac{3}{16}

The solutions to the quadratic equation are:

h = 0, h = - \frac{3}{16}

x^{2} - 26 x + 160 = 0

x, x^{2} + y^{2} + 8 x + 20 = 0

3 (2 + 3 x)^{2} - 9 (2 + 3 x) = 0

(2 + t)^{2} + (9 + t)^{2} = 169

x^{2} - (n - 3) x + 16 = 0

What are the solutions to the equation 1/3 h^2+2/9 h=-5/18 h-7/3 h^2 ?
The solutions to the equation 1/3 h^2+2/9 h=-5/18 h-7/3 h^2 are h=0,h=-3/16
Find the zeros of 1/3 h^2+2/9 h=-5/18 h-7/3 h^2
The zeros of 1/3 h^2+2/9 h=-5/18 h-7/3 h^2 are h=0,h=-3/16