What are the solutions to the equation x^2+8x=15 ?

The solutions to the equation x^2+8x=15 are x=-4+sqrt(31),x=-4-sqrt(31)

Find the zeros of x^2+8x=15

The zeros of x^2+8x=15 are x=-4+sqrt(31),x=-4-sqrt(31)

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x^{2} + 8 x = 15

x = - 4 + 31, x = - 4 - 31

Decimal Notation

x = 1.56776 \dots, x = - 9.56776 \dots

Solution steps

x^{2} + 8 x = 15

Move

15

to the left side

x^{2} + 8 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot (- 15) = 231

x_{1, 2} = \frac{- 8 \pm 2 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 31}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 31}{2 \cdot 1}

x = \frac{- 8 + 2 31}{2 \cdot 1} : - 4 + 31

x = \frac{- 8 - 2 31}{2 \cdot 1} : - 4 - 31

The solutions to the quadratic equation are:

x = - 4 + 31, x = - 4 - 31

ab + a c - b - c

x^{2} + 10 x + 21

\frac{5}{4} = - 4 c + \frac{1}{4}

- \frac{4 d}{7} = 80

π + \frac{π}{6}

What are the solutions to the equation x^2+8x=15 ?
The solutions to the equation x^2+8x=15 are x=-4+sqrt(31),x=-4-sqrt(31)
Find the zeros of x^2+8x=15
The zeros of x^2+8x=15 are x=-4+sqrt(31),x=-4-sqrt(31)