What are the solutions to the equation 2x^2+10x-25=0 ?

The solutions to the equation 2x^2+10x-25=0 are x=(5(sqrt(3)-1))/2 ,x=-(5(1+sqrt(3)))/2

Find the zeros of 2x^2+10x-25=0

The zeros of 2x^2+10x-25=0 are x=(5(sqrt(3)-1))/2 ,x=-(5(1+sqrt(3)))/2

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2 x^{2} + 10 x - 25 = 0

x = \frac{5 ( 3 - 1 )}{2}, x = - \frac{5 ( 1 + 3 )}{2}

Decimal Notation

x = 1.83012 \dots, x = - 6.83012 \dots

Solution steps

2 x^{2} + 10 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 25 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 25) = 103

x_{1, 2} = \frac{- 10 \pm 10 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 10 3}{2 \cdot 2}, x_{2} = \frac{- 10 - 10 3}{2 \cdot 2}

x = \frac{- 10 + 10 3}{2 \cdot 2} : \frac{5 ( 3 - 1 )}{2}

x = \frac{- 10 - 10 3}{2 \cdot 2} : - \frac{5 ( 1 + 3 )}{2}

The solutions to the quadratic equation are:

x = \frac{5 ( 3 - 1 )}{2}, x = - \frac{5 ( 1 + 3 )}{2}

12 = - 7 x - x^{2}

- 24 x^{2} + 4 x - 3 = 0

(x - 5)^{2} = 11

5^{2} + 1 0^{2} = x^{2}

3 x^{2} - 4.4 x - 6.9 = 0

What are the solutions to the equation 2x^2+10x-25=0 ?
The solutions to the equation 2x^2+10x-25=0 are x=(5(sqrt(3)-1))/2 ,x=-(5(1+sqrt(3)))/2
Find the zeros of 2x^2+10x-25=0
The zeros of 2x^2+10x-25=0 are x=(5(sqrt(3)-1))/2 ,x=-(5(1+sqrt(3)))/2