What are the solutions to the equation (x+11)^2=121 ?

The solutions to the equation (x+11)^2=121 are x=0,x=-22

Find the zeros of (x+11)^2=121

The zeros of (x+11)^2=121 are x=0,x=-22

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(x + 11)^{2} = 121

x = 0, x = - 22

Solution steps

(x + 11)^{2} = 121

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 11 = 121 : x = 0

Solve

x + 11 = - 121 : x = - 22

The solutions to the quadratic equation are:

x = 0, x = - 22

9^{2} + 2^{2} = c^{2}

2644.6 = 0.68 \cdot 2.14 \cdot 100 \cdot x \cdot (9.5 - 0.4 \cdot x)

70 x^{2} + 1884.96 x - 320443.2 = 0

x, (\frac{x}{2})^{2} π = 900

7 (2 x - 5)^{2} + 9 = 52

What are the solutions to the equation (x+11)^2=121 ?
The solutions to the equation (x+11)^2=121 are x=0,x=-22
Find the zeros of (x+11)^2=121
The zeros of (x+11)^2=121 are x=0,x=-22