What are the solutions to the equation r^2+80r+2000=0 ?

The solutions to the equation r^2+80r+2000=0 are r=-40+20i,r=-40-20i

Find the zeros of r^2+80r+2000=0

The zeros of r^2+80r+2000=0 are r=-40+20i,r=-40-20i

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r^{2} + 80 r + 2000 = 0

r = - 40 + 20 i, r = - 40 - 20 i

Solution steps

r^{2} + 80 r + 2000 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 \cdot 1 \cdot 2000}{2 \cdot 1}

Simplify

8 0^{2} - 4 \cdot 1 \cdot 2000 : 40 i

r_{1, 2} = \frac{- 80 \pm 40 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 80 + 40 i}{2 \cdot 1}, r_{2} = \frac{- 80 - 40 i}{2 \cdot 1}

r = \frac{- 80 + 40 i}{2 \cdot 1} : - 40 + 20 i

r = \frac{- 80 - 40 i}{2 \cdot 1} : - 40 - 20 i

The solutions to the quadratic equation are:

r = - 40 + 20 i, r = - 40 - 20 i

100 x^{2} - 250 (x - 3)^{2} - 700 = 0

x, y = f (x^{2})

5 X^{2} - 15 X - 50 = 0

(x + 2) (x - 4) = x + 2

(x - 5)^{2} + 2 = 0

What are the solutions to the equation r^2+80r+2000=0 ?
The solutions to the equation r^2+80r+2000=0 are r=-40+20i,r=-40-20i
Find the zeros of r^2+80r+2000=0
The zeros of r^2+80r+2000=0 are r=-40+20i,r=-40-20i