What are the solutions to the equation quadraticformula x^2+9=0 ?

The solutions to the equation quadraticformula x^2+9=0 are x=3i,x=-3i

Find the zeros of quadraticformula x^2+9=0

The zeros of quadraticformula x^2+9=0 are x=3i,x=-3i

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x^{2} + 9 = 0

x = 3 i, x = - 3 i

Solution steps

x^{2} + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

0^{2} - 4 \cdot 1 \cdot 9 : 6 i

x_{1, 2} = \frac{- 0 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 0 - 6 i}{2 \cdot 1}

x = \frac{- 0 + 6 i}{2 \cdot 1} : 3 i

x = \frac{- 0 - 6 i}{2 \cdot 1} : - 3 i

The solutions to the quadratic equation are:

x = 3 i, x = - 3 i

3 x^{2} - 25 x + 3 = - 6 x - 3

6 x^{2} - 8 = 4 x^{2} + 7 x

2 x^{2} + (8 - 2 n) x + 11 = 0

16 x^{2} + 4 x = 0

3 y^{2} - 10 y - 8 = 0

What are the solutions to the equation quadraticformula x^2+9=0 ?
The solutions to the equation quadraticformula x^2+9=0 are x=3i,x=-3i
Find the zeros of quadraticformula x^2+9=0
The zeros of quadraticformula x^2+9=0 are x=3i,x=-3i