What are the solutions to the equation (3z-4)(3z+4)=0 ?

The solutions to the equation (3z-4)(3z+4)=0 are z= 4/3 ,z=-4/3

Find the zeros of (3z-4)(3z+4)=0

The zeros of (3z-4)(3z+4)=0 are z= 4/3 ,z=-4/3

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(3 z - 4) (3 z + 4) = 0

z = \frac{4}{3}, z = - \frac{4}{3}

Decimal Notation

z = 1.33333 \dots, z = - 1.33333 \dots

Solution steps

(3 z - 4) (3 z + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 z - 4 = 0 or 3 z + 4 = 0

Solve

3 z - 4 = 0 : z = \frac{4}{3}

Solve

3 z + 4 = 0 : z = - \frac{4}{3}

The solutions to the quadratic equation are:

z = \frac{4}{3}, z = - \frac{4}{3}

(x 2 + 2 x - 2) \cdot (m x - n) = 5 x 3 + 8 x 2 - 14 x + 4

x^{2} + 62.5 = 0

8 x^{2} - 21 x + 15 = 0

- 0.1 x^{2} + 1800 = 20 x + 550

(w + 4)^{2} = 2 w^{2} + 13 w + 10

What are the solutions to the equation (3z-4)(3z+4)=0 ?
The solutions to the equation (3z-4)(3z+4)=0 are z= 4/3 ,z=-4/3
Find the zeros of (3z-4)(3z+4)=0
The zeros of (3z-4)(3z+4)=0 are z= 4/3 ,z=-4/3