What are the solutions to the equation x^2+x-342=0 ?

The solutions to the equation x^2+x-342=0 are x=18,x=-19

Find the zeros of x^2+x-342=0

The zeros of x^2+x-342=0 are x=18,x=-19

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x^{2} + x - 342 = 0

x = 18, x = - 19

Solution steps

x^{2} + x - 342 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 342 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 342) = 37

x_{1, 2} = \frac{- 1 \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 37}{2 \cdot 1}, x_{2} = \frac{- 1 - 37}{2 \cdot 1}

x = \frac{- 1 + 37}{2 \cdot 1} : 18

x = \frac{- 1 - 37}{2 \cdot 1} : - 19

The solutions to the quadratic equation are:

x = 18, x = - 19

x^{2} - 15 x + 56

x, x^{2} + y^{2} + 2 x - 6 y + 35 = 0

- 0.85 q^{2} + 170 q - 2500 = 0

x^{3} + 2 x^{2} - 15 x - 36 = (x - a)^{2} (x - b)

f^{2} + 1 = 0

What are the solutions to the equation x^2+x-342=0 ?
The solutions to the equation x^2+x-342=0 are x=18,x=-19
Find the zeros of x^2+x-342=0
The zeros of x^2+x-342=0 are x=18,x=-19