What are the solutions to the equation -3x^2+14x-12=0 ?

The solutions to the equation -3x^2+14x-12=0 are x=(7-sqrt(13))/3 ,x=(7+sqrt(13))/3

Find the zeros of -3x^2+14x-12=0

The zeros of -3x^2+14x-12=0 are x=(7-sqrt(13))/3 ,x=(7+sqrt(13))/3

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- 3 x^{2} + 14 x - 12 = 0

x = \frac{7 - 13}{3}, x = \frac{7 + 13}{3}

Decimal Notation

x = 1.13148 \dots, x = 3.53518 \dots

Solution steps

- 3 x^{2} + 14 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 3 ) ( - 12 )}{2 ( - 3 )}

1 4^{2} - 4 (- 3) (- 12) = 213

x_{1, 2} = \frac{- 14 \pm 2 13}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 14 + 2 13}{2 ( - 3 )}, x_{2} = \frac{- 14 - 2 13}{2 ( - 3 )}

x = \frac{- 14 + 2 13}{2 ( - 3 )} : \frac{7 - 13}{3}

x = \frac{- 14 - 2 13}{2 ( - 3 )} : \frac{7 + 13}{3}

The solutions to the quadratic equation are:

x = \frac{7 - 13}{3}, x = \frac{7 + 13}{3}

2 x^{2} + 2 x - 14 = 10

50 (z + 1)^{2} + 25 z = 121 - 41 (z - 1)^{2}

d, \frac{3 ( x - 5 )}{x - 4} = u n d e f in e d

x^{2} + 16 x + 51 = 0

(s + 9) (s - 2) = 0

What are the solutions to the equation -3x^2+14x-12=0 ?
The solutions to the equation -3x^2+14x-12=0 are x=(7-sqrt(13))/3 ,x=(7+sqrt(13))/3
Find the zeros of -3x^2+14x-12=0
The zeros of -3x^2+14x-12=0 are x=(7-sqrt(13))/3 ,x=(7+sqrt(13))/3