What are the solutions to the equation solvefor x,(x+y-2)^2=e^y-1 ?

The solutions to the equation solvefor x,(x+y-2)^2=e^y-1 are x=sqrt(e^y-1)-y+2,x=-sqrt(e^y-1)-y+2

Find the zeros of solvefor x,(x+y-2)^2=e^y-1

The zeros of solvefor x,(x+y-2)^2=e^y-1 are x=sqrt(e^y-1)-y+2,x=-sqrt(e^y-1)-y+2

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solve for

x, (x + y - 2)^{2} = e^{y} - 1

x = e^{y} - 1 - y + 2, x = - e^{y} - 1 - y + 2

Solution steps

(x + y - 2)^{2} = e^{y} - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + y - 2 = e^{y} - 1 : x = e^{y} - 1 - y + 2

Solve

x + y - 2 = - e^{y} - 1 : x = - e^{y} - 1 - y + 2

The solutions to the quadratic equation are:

x = e^{y} - 1 - y + 2, x = - e^{y} - 1 - y + 2

(x - 4)^{2} + (2 x - 15 + 2)^{2} = 5

- 4.91 x^{2} + 2 = 0

x^{2} + (x + 1)^{2} + (x + 2)^{2} = 110

4 x^{2} - x + 4 = 0

70840 - 188 d - 2.35 d^{2} = 1228.8 d + 30.72 d^{2}

What are the solutions to the equation solvefor x,(x+y-2)^2=e^y-1 ?
The solutions to the equation solvefor x,(x+y-2)^2=e^y-1 are x=sqrt(e^y-1)-y+2,x=-sqrt(e^y-1)-y+2
Find the zeros of solvefor x,(x+y-2)^2=e^y-1
The zeros of solvefor x,(x+y-2)^2=e^y-1 are x=sqrt(e^y-1)-y+2,x=-sqrt(e^y-1)-y+2