What are the solutions to the equation x(x+2)=2 ?

The solutions to the equation x(x+2)=2 are x=-1+sqrt(3),x=-1-sqrt(3)

Find the zeros of x(x+2)=2

The zeros of x(x+2)=2 are x=-1+sqrt(3),x=-1-sqrt(3)

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x (x + 2) = 2

x = - 1 + 3, x = - 1 - 3

Decimal Notation

x = 0.73205 \dots, x = - 2.73205 \dots

Solution steps

x (x + 2) = 2

Expand

x (x + 2) : x^{2} + 2 x

x^{2} + 2 x = 2

Move

2

to the left side

x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 2) = 23

x_{1, 2} = \frac{- 2 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 3}{2 \cdot 1}

x = \frac{- 2 + 2 3}{2 \cdot 1} : - 1 + 3

x = \frac{- 2 - 2 3}{2 \cdot 1} : - 1 - 3

The solutions to the quadratic equation are:

x = - 1 + 3, x = - 1 - 3

y^{2} - 2 y - 3 = y - 3

x^{2} + 3 x - 36 = 0

(4 x - 3) (x + 1) = 0

(x - 5)^{2} + (x + 3)^{2} = 49

(- \frac{2}{3} y)^{2} + 4 y = 0

What are the solutions to the equation x(x+2)=2 ?
The solutions to the equation x(x+2)=2 are x=-1+sqrt(3),x=-1-sqrt(3)
Find the zeros of x(x+2)=2
The zeros of x(x+2)=2 are x=-1+sqrt(3),x=-1-sqrt(3)