What are the solutions to the equation 2x^2-5x-20=0 ?

The solutions to the equation 2x^2-5x-20=0 are x=(5+sqrt(185))/4 ,x=(5-sqrt(185))/4

Find the zeros of 2x^2-5x-20=0

The zeros of 2x^2-5x-20=0 are x=(5+sqrt(185))/4 ,x=(5-sqrt(185))/4

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2 x^{2} - 5 x - 20 = 0

x = \frac{5 + 185}{4}, x = \frac{5 - 185}{4}

Decimal Notation

x = 4.65036 \dots, x = - 2.15036 \dots

Solution steps

2 x^{2} - 5 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 20 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 20) = 185

x_{1, 2} = \frac{- ( - 5 ) \pm 185}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 185}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 185}{2 \cdot 2}

x = \frac{- ( - 5 ) + 185}{2 \cdot 2} : \frac{5 + 185}{4}

x = \frac{- ( - 5 ) - 185}{2 \cdot 2} : \frac{5 - 185}{4}

The solutions to the quadratic equation are:

x = \frac{5 + 185}{4}, x = \frac{5 - 185}{4}

a, (ab c) \cdot (c ba) = 466456

x^{2} + (x + 2)^{2} = 50

- 8 x^{2} - 24 x = 0

c, 8 c^{2} x y = (x^{2} - y^{2})^{2}

- 12 x^{2} + 18 x - 4 = 0

What are the solutions to the equation 2x^2-5x-20=0 ?
The solutions to the equation 2x^2-5x-20=0 are x=(5+sqrt(185))/4 ,x=(5-sqrt(185))/4
Find the zeros of 2x^2-5x-20=0
The zeros of 2x^2-5x-20=0 are x=(5+sqrt(185))/4 ,x=(5-sqrt(185))/4