What are the solutions to the equation 4x^2+5x=-9 ?

The solutions to the equation 4x^2+5x=-9 are x=-5/8+i(sqrt(119))/8 ,x=-5/8-i(sqrt(119))/8

Find the zeros of 4x^2+5x=-9

The zeros of 4x^2+5x=-9 are x=-5/8+i(sqrt(119))/8 ,x=-5/8-i(sqrt(119))/8

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4 x^{2} + 5 x = - 9

x = - \frac{5}{8} + i \frac{119}{8}, x = - \frac{5}{8} - i \frac{119}{8}

Solution steps

4 x^{2} + 5 x = - 9

Move

9

to the left side

4 x^{2} + 5 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

Simplify

5^{2} - 4 \cdot 4 \cdot 9 : 119 i

x_{1, 2} = \frac{- 5 \pm 119 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 5 + 119 i}{2 \cdot 4}, x_{2} = \frac{- 5 - 119 i}{2 \cdot 4}

x = \frac{- 5 + 119 i}{2 \cdot 4} : - \frac{5}{8} + i \frac{119}{8}

x = \frac{- 5 - 119 i}{2 \cdot 4} : - \frac{5}{8} - i \frac{119}{8}

The solutions to the quadratic equation are:

x = - \frac{5}{8} + i \frac{119}{8}, x = - \frac{5}{8} - i \frac{119}{8}

(x + 6)^{2} - 6 = 0

2 x^{2} + 10 x = 28

\frac{y ^{2} - 6}{2} = y + 1

0.1 x^{2} - 30 x + 1890 = 0

3 x^{2} - 18 x - 81 = 0

What are the solutions to the equation 4x^2+5x=-9 ?
The solutions to the equation 4x^2+5x=-9 are x=-5/8+i(sqrt(119))/8 ,x=-5/8-i(sqrt(119))/8
Find the zeros of 4x^2+5x=-9
The zeros of 4x^2+5x=-9 are x=-5/8+i(sqrt(119))/8 ,x=-5/8-i(sqrt(119))/8