What are the solutions to the equation x^2=b^2+2b^2 ?

The solutions to the equation x^2=b^2+2b^2 are x=bsqrt(3),x=-bsqrt(3)

Find the zeros of x^2=b^2+2b^2

The zeros of x^2=b^2+2b^2 are x=bsqrt(3),x=-bsqrt(3)

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x^{2} = b^{2} + 2 b^{2}

x = b 3, x = - b 3

Solution steps

x^{2} = b^{2} + 2 b^{2}

Add similar elements:

b^{2} + 2 b^{2} = 3 b^{2}

x^{2} = 3 b^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 3 b^{2}, x = - 3 b^{2}

Simplify

3 b^{2} : b 3

Simplify

- 3 b^{2} : - b 3

x = b 3, x = - b 3

x, x^{2} - 2 x y + y^{2} - 2 x - 2 y = 0

x - x^{2} = 1

n^{2} - n = 12

x^{2} - 10 x = 56

3 x (x - 2) = 7 x^{2} - 7 x

What are the solutions to the equation x^2=b^2+2b^2 ?
The solutions to the equation x^2=b^2+2b^2 are x=bsqrt(3),x=-bsqrt(3)
Find the zeros of x^2=b^2+2b^2
The zeros of x^2=b^2+2b^2 are x=bsqrt(3),x=-bsqrt(3)