What are the solutions to the equation x^2+28x-29=0 ?

The solutions to the equation x^2+28x-29=0 are x=1,x=-29

Find the zeros of x^2+28x-29=0

The zeros of x^2+28x-29=0 are x=1,x=-29

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x^{2} + 28 x - 29 = 0

x = 1, x = - 29

Solution steps

x^{2} + 28 x - 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 1 \cdot ( - 29 )}{2 \cdot 1}

2 8^{2} - 4 \cdot 1 \cdot (- 29) = 30

x_{1, 2} = \frac{- 28 \pm 30}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 28 + 30}{2 \cdot 1}, x_{2} = \frac{- 28 - 30}{2 \cdot 1}

x = \frac{- 28 + 30}{2 \cdot 1} : 1

x = \frac{- 28 - 30}{2 \cdot 1} : - 29

The solutions to the quadratic equation are:

x = 1, x = - 29

2 x^{2} - 4 = 4

- 3 x^{2} - 4 x - 20 = 0

(x + 1)^{2} + 4 = 0

6 x^{2} = - 12 x

3 x^{2} + 18 x + 20 = 0

What are the solutions to the equation x^2+28x-29=0 ?
The solutions to the equation x^2+28x-29=0 are x=1,x=-29
Find the zeros of x^2+28x-29=0
The zeros of x^2+28x-29=0 are x=1,x=-29