What are the solutions to the equation 81x^2-108x+36=0 ?

The solutions to the equation 81x^2-108x+36=0 are x= 2/3

Find the zeros of 81x^2-108x+36=0

The zeros of 81x^2-108x+36=0 are x= 2/3

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81 x^{2} - 108 x + 36 = 0

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

81 x^{2} - 108 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 108 ) \pm ( - 108 ) ^{2} - 4 \cdot 81 \cdot 36}{2 \cdot 81}

(- 108)^{2} - 4 \cdot 81 \cdot 36 = 0

x_{1, 2} = \frac{- ( - 108 ) \pm 0}{2 \cdot 81}

x = \frac{- ( - 108 )}{2 \cdot 81}

\frac{- ( - 108 )}{2 \cdot 81} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

a^{2} + 3 5^{2} = 3 7^{2}

3 x^{2} - 32 x + 13 = - 10 x + 6

2 x^{2} - 3 x - 2 = 0

15 x^{2} + 13 x - 20 = 0

x^{2} + 6 x + c = 0

What are the solutions to the equation 81x^2-108x+36=0 ?
The solutions to the equation 81x^2-108x+36=0 are x= 2/3
Find the zeros of 81x^2-108x+36=0
The zeros of 81x^2-108x+36=0 are x= 2/3