What are the solutions to the equation 2x^2+20x+100=0 ?

The solutions to the equation 2x^2+20x+100=0 are x=-5+5i,x=-5-5i

Find the zeros of 2x^2+20x+100=0

The zeros of 2x^2+20x+100=0 are x=-5+5i,x=-5-5i

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2 x^{2} + 20 x + 100 = 0

x = - 5 + 5 i, x = - 5 - 5 i

Solution steps

2 x^{2} + 20 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 \cdot 100}{2 \cdot 2}

Simplify

2 0^{2} - 4 \cdot 2 \cdot 100 : 20 i

x_{1, 2} = \frac{- 20 \pm 20 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 20 i}{2 \cdot 2}, x_{2} = \frac{- 20 - 20 i}{2 \cdot 2}

x = \frac{- 20 + 20 i}{2 \cdot 2} : - 5 + 5 i

x = \frac{- 20 - 20 i}{2 \cdot 2} : - 5 - 5 i

The solutions to the quadratic equation are:

x = - 5 + 5 i, x = - 5 - 5 i

x^{2} - 20 x + 150 = 0

- k^{2} + 20 k + 12 = 0

6^{2} = a^{2} - 8^{2}

x^{2} + (- 3) x + (- 3) + 8 = 0

x + 6 = x^{2} - 2

What are the solutions to the equation 2x^2+20x+100=0 ?
The solutions to the equation 2x^2+20x+100=0 are x=-5+5i,x=-5-5i
Find the zeros of 2x^2+20x+100=0
The zeros of 2x^2+20x+100=0 are x=-5+5i,x=-5-5i