What are the solutions to the equation 13x^2-5x+12=0 ?

The solutions to the equation 13x^2-5x+12=0 are x= 5/26+i(sqrt(599))/(26),x= 5/26-i(sqrt(599))/(26)

Find the zeros of 13x^2-5x+12=0

The zeros of 13x^2-5x+12=0 are x= 5/26+i(sqrt(599))/(26),x= 5/26-i(sqrt(599))/(26)

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13 x^{2} - 5 x + 12 = 0

x = \frac{5}{26} + i \frac{599}{26}, x = \frac{5}{26} - i \frac{599}{26}

Solution steps

13 x^{2} - 5 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 13 \cdot 12}{2 \cdot 13}

Simplify

(- 5)^{2} - 4 \cdot 13 \cdot 12 : 599 i

x_{1, 2} = \frac{- ( - 5 ) \pm 599 i}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 599 i}{2 \cdot 13}, x_{2} = \frac{- ( - 5 ) - 599 i}{2 \cdot 13}

x = \frac{- ( - 5 ) + 599 i}{2 \cdot 13} : \frac{5}{26} + i \frac{599}{26}

x = \frac{- ( - 5 ) - 599 i}{2 \cdot 13} : \frac{5}{26} - i \frac{599}{26}

The solutions to the quadratic equation are:

x = \frac{5}{26} + i \frac{599}{26}, x = \frac{5}{26} - i \frac{599}{26}

x^{2} + 16 x = 30

z, x^{2} + y^{2} + z^{2} = 2 z

y, X^{2} + y^{2} = 3.24

4 0^{2} + x^{2} = 5 0^{2}

64 x^{2} - 144 = - 23

What are the solutions to the equation 13x^2-5x+12=0 ?
The solutions to the equation 13x^2-5x+12=0 are x= 5/26+i(sqrt(599))/(26),x= 5/26-i(sqrt(599))/(26)
Find the zeros of 13x^2-5x+12=0
The zeros of 13x^2-5x+12=0 are x= 5/26+i(sqrt(599))/(26),x= 5/26-i(sqrt(599))/(26)