What is (3x)/(10)+1>= 1/5-x/(10) ?

The solution to (3x)/(10)+1>= 1/5-x/(10) is x>=-2

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(3x)/(10)+1>= 1/5-x/(10)

\frac{3 x}{10} + 1 \geq \frac{1}{5} - \frac{x}{10}

x \geq - 2

Interval Notation

[- 2, \infty)

Solution steps

\frac{3 x}{10} + 1 \geq \frac{1}{5} - \frac{x}{10}

Move

\frac{x}{10}

to the left side

\frac{2 x}{5} + 1 \geq \frac{1}{5}

Move

1

to the right side

\frac{2 x}{5} \geq - \frac{4}{5}

Multiply both sides by

5

2 x \geq - 4

Divide both sides by

2

x \geq - 2

\frac{- 20 x ^{3} y ^{2}}{5 x ^{7} y ^{2}}

- 2 (- \frac{1}{2})

x^{2} - 4 x - 32 > 0

\frac{\frac{1}{x ^{2}} + \frac{1}{y ^{2}}}{\frac{1}{x} - \frac{1}{y}}

0 = - \frac{2}{3} x - 2

What is (3x)/(10)+1>= 1/5-x/(10) ?
The solution to (3x)/(10)+1>= 1/5-x/(10) is x>=-2