What are the solutions to the equation x^2+x=342 ?

The solutions to the equation x^2+x=342 are x=18,x=-19

Find the zeros of x^2+x=342

The zeros of x^2+x=342 are x=18,x=-19

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x^{2} + x = 342

x = 18, x = - 19

Solution steps

x^{2} + x = 342

Move

342

to the left side

x^{2} + x - 342 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 342 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 342) = 37

x_{1, 2} = \frac{- 1 \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 37}{2 \cdot 1}, x_{2} = \frac{- 1 - 37}{2 \cdot 1}

x = \frac{- 1 + 37}{2 \cdot 1} : 18

x = \frac{- 1 - 37}{2 \cdot 1} : - 19

The solutions to the quadratic equation are:

x = 18, x = - 19

x, (x - y)^{2} + x y = 1

x, x^{2} + x y - y^{2} = 16

b^{2} + 5 b = 32 + b

(\frac{1}{7})^{2} + y^{2} = 1

2.7 \cdot 1 0^{- 9} x^{2} - 16 \cdot 1 0^{- 5} x + 0.5 = 0

What are the solutions to the equation x^2+x=342 ?
The solutions to the equation x^2+x=342 are x=18,x=-19
Find the zeros of x^2+x=342
The zeros of x^2+x=342 are x=18,x=-19