What are the solutions to the equation solvefor y,2x+y^2=48 ?

The solutions to the equation solvefor y,2x+y^2=48 are y=sqrt(48-2x),y=-sqrt(48-2x)

Find the zeros of solvefor y,2x+y^2=48

The zeros of solvefor y,2x+y^2=48 are y=sqrt(48-2x),y=-sqrt(48-2x)

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solve for

y, 2 x + y^{2} = 48

y = 48 - 2 x, y = - 48 - 2 x

Solution steps

2 x + y^{2} = 48

Move

2 x

to the right side

y^{2} = 48 - 2 x

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 48 - 2 x, y = - 48 - 2 x

3 g^{2} - 10 g = 8

36 - \frac{1}{4} y^{2} = 0

- 0.2 x^{2} + 80 = 4 x + 20

5 x^{2} + 2 = 8 x

565.26 x^{(2)} - 11195 x + 26725 = 1616748

What are the solutions to the equation solvefor y,2x+y^2=48 ?
The solutions to the equation solvefor y,2x+y^2=48 are y=sqrt(48-2x),y=-sqrt(48-2x)
Find the zeros of solvefor y,2x+y^2=48
The zeros of solvefor y,2x+y^2=48 are y=sqrt(48-2x),y=-sqrt(48-2x)