What are the solutions to the equation q^2-4=0 ?

The solutions to the equation q^2-4=0 are q=2,q=-2

Find the zeros of q^2-4=0

The zeros of q^2-4=0 are q=2,q=-2

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q^{2} - 4 = 0

q = 2, q = - 2

Solution steps

q^{2} - 4 = 0

Move

4

to the right side

q^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 4, q = - 4

4 = 2

- 4 = - 2

q = 2, q = - 2

x, x^{2} y + x y^{2} = 2

x, z = y^{2} - 3 x y + 2 x^{2} - 4

(2 x - 1)^{2} = (x - 1) (x - 3) + 1

3 y - 10 + y^{2} = 0

- 7 - y^{2} = - 25

What are the solutions to the equation q^2-4=0 ?
The solutions to the equation q^2-4=0 are q=2,q=-2
Find the zeros of q^2-4=0
The zeros of q^2-4=0 are q=2,q=-2