What are the solutions to the equation v^2-5v+6=0 ?

The solutions to the equation v^2-5v+6=0 are v=3,v=2

Find the zeros of v^2-5v+6=0

The zeros of v^2-5v+6=0 are v=3,v=2

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v^{2} - 5 v + 6 = 0

v = 3, v = 2

Solution steps

v^{2} - 5 v + 6 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

v_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, v_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

v = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

v = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

v = 3, v = 2

x, \frac{x ^{2}}{c ^{2}} - \frac{y ^{9}}{d ^{2}} = π x

39 x^{2} - 83 x = 56

(2 - x) (4 - x) + 2 = 0

C = 0.5 x^{2} + 15 x + 5000

- 12 x - x^{2} = 0

What are the solutions to the equation v^2-5v+6=0 ?
The solutions to the equation v^2-5v+6=0 are v=3,v=2
Find the zeros of v^2-5v+6=0
The zeros of v^2-5v+6=0 are v=3,v=2