What are the solutions to the equation 49x^2-70x-25=0 ?

The solutions to the equation 49x^2-70x-25=0 are x=(5(1+sqrt(2)))/7 ,x=(5(1-sqrt(2)))/7

Find the zeros of 49x^2-70x-25=0

The zeros of 49x^2-70x-25=0 are x=(5(1+sqrt(2)))/7 ,x=(5(1-sqrt(2)))/7

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49 x^{2} - 70 x - 25 = 0

x = \frac{5 ( 1 + 2 )}{7}, x = \frac{5 ( 1 - 2 )}{7}

Decimal Notation

x = 1.72443 \dots, x = - 0.29586 \dots

Solution steps

49 x^{2} - 70 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 70 ) \pm ( - 70 ) ^{2} - 4 \cdot 49 ( - 25 )}{2 \cdot 49}

(- 70)^{2} - 4 \cdot 49 (- 25) = 702

x_{1, 2} = \frac{- ( - 70 ) \pm 70 2}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- ( - 70 ) + 70 2}{2 \cdot 49}, x_{2} = \frac{- ( - 70 ) - 70 2}{2 \cdot 49}

x = \frac{- ( - 70 ) + 70 2}{2 \cdot 49} : \frac{5 ( 1 + 2 )}{7}

x = \frac{- ( - 70 ) - 70 2}{2 \cdot 49} : \frac{5 ( 1 - 2 )}{7}

The solutions to the quadratic equation are:

x = \frac{5 ( 1 + 2 )}{7}, x = \frac{5 ( 1 - 2 )}{7}

0 = - 2 x^{2} + 40 x - 72

0.9 x^{2} - 10 x - 28 = 0

x (2 x - 3) = x

81 x^{2} + 196 = 0

x, f (x + 2) = 3 x^{2} - 2 x + 1

What are the solutions to the equation 49x^2-70x-25=0 ?
The solutions to the equation 49x^2-70x-25=0 are x=(5(1+sqrt(2)))/7 ,x=(5(1-sqrt(2)))/7
Find the zeros of 49x^2-70x-25=0
The zeros of 49x^2-70x-25=0 are x=(5(1+sqrt(2)))/7 ,x=(5(1-sqrt(2)))/7