What are the solutions to the equation k^2-4k+5=0 ?

The solutions to the equation k^2-4k+5=0 are k=2+i,k=2-i

Find the zeros of k^2-4k+5=0

The zeros of k^2-4k+5=0 are k=2+i,k=2-i

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k^{2} - 4 k + 5 = 0

k = 2 + i, k = 2 - i

Solution steps

k^{2} - 4 k + 5 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

Simplify

(- 4)^{2} - 4 \cdot 1 \cdot 5 : 2 i

k_{1, 2} = \frac{- ( - 4 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 4 ) + 2 i}{2 \cdot 1}, k_{2} = \frac{- ( - 4 ) - 2 i}{2 \cdot 1}

k = \frac{- ( - 4 ) + 2 i}{2 \cdot 1} : 2 + i

k = \frac{- ( - 4 ) - 2 i}{2 \cdot 1} : 2 - i

The solutions to the quadratic equation are:

k = 2 + i, k = 2 - i

2 y \leq 4

48 x + 56 y

\frac{1}{4} \cdot \frac{1}{4}

4 x^{2} + 168 x - 540 = 0

\frac{x}{6} - \frac{x}{10} = \frac{1}{6}

What are the solutions to the equation k^2-4k+5=0 ?
The solutions to the equation k^2-4k+5=0 are k=2+i,k=2-i
Find the zeros of k^2-4k+5=0
The zeros of k^2-4k+5=0 are k=2+i,k=2-i