What are the solutions to the equation 6x^2+2x=216 ?

The solutions to the equation 6x^2+2x=216 are x=(-1+sqrt(1297))/6 ,x=-(1+sqrt(1297))/6

Find the zeros of 6x^2+2x=216

The zeros of 6x^2+2x=216 are x=(-1+sqrt(1297))/6 ,x=-(1+sqrt(1297))/6

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6 x^{2} + 2 x = 216

x = \frac{- 1 + 1297}{6}, x = - \frac{1 + 1297}{6}

Decimal Notation

x = 5.83564 \dots, x = - 6.16898 \dots

Solution steps

6 x^{2} + 2 x = 216

Move

216

to the left side

6 x^{2} + 2 x - 216 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 216 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 216) = 21297

x_{1, 2} = \frac{- 2 \pm 2 1297}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 1297}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 1297}{2 \cdot 6}

x = \frac{- 2 + 2 1297}{2 \cdot 6} : \frac{- 1 + 1297}{6}

x = \frac{- 2 - 2 1297}{2 \cdot 6} : - \frac{1 + 1297}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 1297}{6}, x = - \frac{1 + 1297}{6}

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4 x^{2} + 28 x + 49 = 0

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What are the solutions to the equation 6x^2+2x=216 ?
The solutions to the equation 6x^2+2x=216 are x=(-1+sqrt(1297))/6 ,x=-(1+sqrt(1297))/6
Find the zeros of 6x^2+2x=216
The zeros of 6x^2+2x=216 are x=(-1+sqrt(1297))/6 ,x=-(1+sqrt(1297))/6