What are the solutions to the equation (x-2)(x+4)-2(x-4)=0 ?

The solutions to the equation (x-2)(x+4)-2(x-4)=0 are x=0

Find the zeros of (x-2)(x+4)-2(x-4)=0

The zeros of (x-2)(x+4)-2(x-4)=0 are x=0

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(x - 2) (x + 4) - 2 (x - 4) = 0

x = 0

Solution steps

(x - 2) (x + 4) - 2 (x - 4) = 0

Expand

(x - 2) (x + 4) - 2 (x - 4) : x^{2}

x^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot 0 = 0

x_{1, 2} = \frac{- 0 \pm 0}{2 \cdot 1}

x = \frac{- 0}{2 \cdot 1}

\frac{- 0}{2 \cdot 1} = 0

x = 0

The solution to the quadratic equation is:

x = 0

3 y^{2} - 4 y + 2 = 2 (y - 3) 2

- 4 x^{2} + 6 x = 0

x^{2} - 6 x + 14

88 (t) = \frac{t ^{2}}{2 - 200}

x (x - 5) = 750

What are the solutions to the equation (x-2)(x+4)-2(x-4)=0 ?
The solutions to the equation (x-2)(x+4)-2(x-4)=0 are x=0
Find the zeros of (x-2)(x+4)-2(x-4)=0
The zeros of (x-2)(x+4)-2(x-4)=0 are x=0