What are the solutions to the equation 3u^2+7u-6=0 ?

The solutions to the equation 3u^2+7u-6=0 are u= 2/3 ,u=-3

Find the zeros of 3u^2+7u-6=0

The zeros of 3u^2+7u-6=0 are u= 2/3 ,u=-3

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3 u^{2} + 7 u - 6 = 0

u = \frac{2}{3}, u = - 3

Decimal Notation

u = 0.66666 \dots, u = - 3

Solution steps

3 u^{2} + 7 u - 6 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 6 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 6) = 11

u_{1, 2} = \frac{- 7 \pm 11}{2 \cdot 3}

Separate the solutions

u_{1} = \frac{- 7 + 11}{2 \cdot 3}, u_{2} = \frac{- 7 - 11}{2 \cdot 3}

u = \frac{- 7 + 11}{2 \cdot 3} : \frac{2}{3}

u = \frac{- 7 - 11}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

u = \frac{2}{3}, u = - 3

5 x^{2} + 215 x + 3 = 0

x^{2} - 4 x + 2 = 0

x, y = a (x - p)^{2} + q

- x^{2} + 2 x + 4

2 x - 1 = - x^{2} + x + 3

What are the solutions to the equation 3u^2+7u-6=0 ?
The solutions to the equation 3u^2+7u-6=0 are u= 2/3 ,u=-3
Find the zeros of 3u^2+7u-6=0
The zeros of 3u^2+7u-6=0 are u= 2/3 ,u=-3