What are the solutions to the equation 4x^2+7x-8=-8x-4 ?

The solutions to the equation 4x^2+7x-8=-8x-4 are x= 1/4 ,x=-4

Find the zeros of 4x^2+7x-8=-8x-4

The zeros of 4x^2+7x-8=-8x-4 are x= 1/4 ,x=-4

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4 x^{2} + 7 x - 8 = - 8 x - 4

x = \frac{1}{4}, x = - 4

Decimal Notation

x = 0.25, x = - 4

Solution steps

4 x^{2} + 7 x - 8 = - 8 x - 4

Move

4

to the left side

4 x^{2} + 7 x - 4 = - 8 x

Move

8 x

to the left side

4 x^{2} + 15 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 4 ( - 4 )}{2 \cdot 4}

1 5^{2} - 4 \cdot 4 (- 4) = 17

x_{1, 2} = \frac{- 15 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 15 + 17}{2 \cdot 4}, x_{2} = \frac{- 15 - 17}{2 \cdot 4}

x = \frac{- 15 + 17}{2 \cdot 4} : \frac{1}{4}

x = \frac{- 15 - 17}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - 4

2 (3 x + 4) = \frac{10 x + 30}{2} 210 x + 30

3 x^{2} + 12 x - 4 = 0

x^{2} + 6 x = 25

x^{2} + 7.5 x - 4 = 0

\frac{1}{2} x^{2} - 12 = 18

What are the solutions to the equation 4x^2+7x-8=-8x-4 ?
The solutions to the equation 4x^2+7x-8=-8x-4 are x= 1/4 ,x=-4
Find the zeros of 4x^2+7x-8=-8x-4
The zeros of 4x^2+7x-8=-8x-4 are x= 1/4 ,x=-4