What are the solutions to the equation -5x^2+2x+8=0 ?

The solutions to the equation -5x^2+2x+8=0 are x=-(-1+sqrt(41))/5 ,x=(1+sqrt(41))/5

Find the zeros of -5x^2+2x+8=0

The zeros of -5x^2+2x+8=0 are x=-(-1+sqrt(41))/5 ,x=(1+sqrt(41))/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- 5 x^{2} + 2 x + 8 = 0

x = - \frac{- 1 + 41}{5}, x = \frac{1 + 41}{5}

Decimal Notation

x = - 1.08062 \dots, x = 1.48062 \dots

Solution steps

- 5 x^{2} + 2 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 5 ) \cdot 8}{2 ( - 5 )}

2^{2} - 4 (- 5) \cdot 8 = 241

x_{1, 2} = \frac{- 2 \pm 2 41}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 41}{2 ( - 5 )}, x_{2} = \frac{- 2 - 2 41}{2 ( - 5 )}

x = \frac{- 2 + 2 41}{2 ( - 5 )} : - \frac{- 1 + 41}{5}

x = \frac{- 2 - 2 41}{2 ( - 5 )} : \frac{1 + 41}{5}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 41}{5}, x = \frac{1 + 41}{5}

2 x^{2} - 82 = 16

x^{2} = 5^{2} + 9^{2}

15 n^{2} - 12 - 8 n = 0

x^{2} = - 3, x^{1} = 0

12 x^{2} - 384 x + 2304 = 0

What are the solutions to the equation -5x^2+2x+8=0 ?
The solutions to the equation -5x^2+2x+8=0 are x=-(-1+sqrt(41))/5 ,x=(1+sqrt(41))/5
Find the zeros of -5x^2+2x+8=0
The zeros of -5x^2+2x+8=0 are x=-(-1+sqrt(41))/5 ,x=(1+sqrt(41))/5