What are the solutions to the equation 1.1t^2-1.2t+0.3=0 ?

The solutions to the equation 1.1t^2-1.2t+0.3=0 are t=(6+sqrt(3))/(11),t=(6-sqrt(3))/(11)

Find the zeros of 1.1t^2-1.2t+0.3=0

The zeros of 1.1t^2-1.2t+0.3=0 are t=(6+sqrt(3))/(11),t=(6-sqrt(3))/(11)

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1.1 t^{2} - 1.2 t + 0.3 = 0

t = \frac{6 + 3}{11}, t = \frac{6 - 3}{11}

Decimal Notation

t = 0.70291 \dots, t = 0.38799 \dots

Solution steps

1.1 t^{2} - 1.2 t + 0.3 = 0

Multiply both sides by

10

11 t^{2} - 12 t + 3 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 11 \cdot 3}{2 \cdot 11}

(- 12)^{2} - 4 \cdot 11 \cdot 3 = 23

t_{1, 2} = \frac{- ( - 12 ) \pm 2 3}{2 \cdot 11}

Separate the solutions

t_{1} = \frac{- ( - 12 ) + 2 3}{2 \cdot 11}, t_{2} = \frac{- ( - 12 ) - 2 3}{2 \cdot 11}

t = \frac{- ( - 12 ) + 2 3}{2 \cdot 11} : \frac{6 + 3}{11}

t = \frac{- ( - 12 ) - 2 3}{2 \cdot 11} : \frac{6 - 3}{11}

The solutions to the quadratic equation are:

t = \frac{6 + 3}{11}, t = \frac{6 - 3}{11}

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375 x^{2} - 31815 x + 675 = 0

45 m^{2} + 725 m + 144 = 0

111 x^{2} - 468 x + 456 = 0

What are the solutions to the equation 1.1t^2-1.2t+0.3=0 ?
The solutions to the equation 1.1t^2-1.2t+0.3=0 are t=(6+sqrt(3))/(11),t=(6-sqrt(3))/(11)
Find the zeros of 1.1t^2-1.2t+0.3=0
The zeros of 1.1t^2-1.2t+0.3=0 are t=(6+sqrt(3))/(11),t=(6-sqrt(3))/(11)