What are the solutions to the equation 54500=(550+25x)(96-3x) ?

The solutions to the equation 54500=(550+25x)(96-3x) are x=(15-sqrt(21))/3 ,x=(15+sqrt(21))/3

Find the zeros of 54500=(550+25x)(96-3x)

The zeros of 54500=(550+25x)(96-3x) are x=(15-sqrt(21))/3 ,x=(15+sqrt(21))/3

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54500 = (550 + 25 x) (96 - 3 x)

x = \frac{15 - 21}{3}, x = \frac{15 + 21}{3}

Decimal Notation

x = 3.47247 \dots, x = 6.52752 \dots

Solution steps

54500 = (550 + 25 x) (96 - 3 x)

Expand

(550 + 25 x) (96 - 3 x) : 52800 + 750 x - 75 x^{2}

54500 = 52800 + 750 x - 75 x^{2}

Switch sides

52800 + 750 x - 75 x^{2} = 54500

Move

54500

to the left side

- 75 x^{2} + 750 x - 1700 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 750 \pm 75 0 ^{2} - 4 ( - 75 ) ( - 1700 )}{2 ( - 75 )}

75 0^{2} - 4 (- 75) (- 1700) = 5021

x_{1, 2} = \frac{- 750 \pm 50 21}{2 ( - 75 )}

Separate the solutions

x_{1} = \frac{- 750 + 50 21}{2 ( - 75 )}, x_{2} = \frac{- 750 - 50 21}{2 ( - 75 )}

x = \frac{- 750 + 50 21}{2 ( - 75 )} : \frac{15 - 21}{3}

x = \frac{- 750 - 50 21}{2 ( - 75 )} : \frac{15 + 21}{3}

The solutions to the quadratic equation are:

x = \frac{15 - 21}{3}, x = \frac{15 + 21}{3}

x^{2} - 3 x - 26 = 0

(r^{2} + 1) = 0

x, z = 5 - x^{2} - y^{2}

4 x^{2} = 4 x - 17

8 x = 2 x^{2}

What are the solutions to the equation 54500=(550+25x)(96-3x) ?
The solutions to the equation 54500=(550+25x)(96-3x) are x=(15-sqrt(21))/3 ,x=(15+sqrt(21))/3
Find the zeros of 54500=(550+25x)(96-3x)
The zeros of 54500=(550+25x)(96-3x) are x=(15-sqrt(21))/3 ,x=(15+sqrt(21))/3