What are the solutions to the equation x^2-13x-420=0 ?

The solutions to the equation x^2-13x-420=0 are x=28,x=-15

Find the zeros of x^2-13x-420=0

The zeros of x^2-13x-420=0 are x=28,x=-15

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x^{2} - 13 x - 420 = 0

x = 28, x = - 15

Solution steps

x^{2} - 13 x - 420 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot ( - 420 )}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot (- 420) = 43

x_{1, 2} = \frac{- ( - 13 ) \pm 43}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 43}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 43}{2 \cdot 1}

x = \frac{- ( - 13 ) + 43}{2 \cdot 1} : 28

x = \frac{- ( - 13 ) - 43}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 28, x = - 15

x, p (x) = y (x^{2} + 2) - x (y^{2} + 2)

- X^{2} - 2 X + 1 = 0

x, f^{- 1} (x) = 2 - (x - 3)^{2}

1 x^{2} - 7 x + 10 = 0

- y^{2} + 25 y - 144 = 0

What are the solutions to the equation x^2-13x-420=0 ?
The solutions to the equation x^2-13x-420=0 are x=28,x=-15
Find the zeros of x^2-13x-420=0
The zeros of x^2-13x-420=0 are x=28,x=-15