What are the solutions to the equation z^2+2z^2+z-z+9=0 ?

The solutions to the equation z^2+2z^2+z-z+9=0 are z=sqrt(3)i,z=-sqrt(3)i

Find the zeros of z^2+2z^2+z-z+9=0

The zeros of z^2+2z^2+z-z+9=0 are z=sqrt(3)i,z=-sqrt(3)i

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z^{2} + 2 z^{2} + z - z + 9 = 0

z = 3 i, z = - 3 i

Solution steps

z^{2} + 2 z^{2} + z - z + 9 = 0

Refine

3 z^{2} + 9 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

0^{2} - 4 \cdot 3 \cdot 9 : 63 i

z_{1, 2} = \frac{- 0 \pm 6 3 i}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 0 + 6 3 i}{2 \cdot 3}, z_{2} = \frac{- 0 - 6 3 i}{2 \cdot 3}

z = \frac{- 0 + 6 3 i}{2 \cdot 3} : 3 i

z = \frac{- 0 - 6 3 i}{2 \cdot 3} : - 3 i

The solutions to the quadratic equation are:

z = 3 i, z = - 3 i

x, - x^{2} - 2 y^{3} + 2 y^{2} = 0

2 x^{2} + 4 x - 6

2 x^{2} - 12 x + 18 = 0

4 x^{2} - 8 x + 10 = 0

x^{2} - 14 x - 15

What are the solutions to the equation z^2+2z^2+z-z+9=0 ?
The solutions to the equation z^2+2z^2+z-z+9=0 are z=sqrt(3)i,z=-sqrt(3)i
Find the zeros of z^2+2z^2+z-z+9=0
The zeros of z^2+2z^2+z-z+9=0 are z=sqrt(3)i,z=-sqrt(3)i