What are the solutions to the equation x^2-8x-36=0 ?

The solutions to the equation x^2-8x-36=0 are x=2(2+sqrt(13)),x=2(2-sqrt(13))

Find the zeros of x^2-8x-36=0

The zeros of x^2-8x-36=0 are x=2(2+sqrt(13)),x=2(2-sqrt(13))

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x^{2} - 8 x - 36 = 0

x = 2 (2 + 13), x = 2 (2 - 13)

Decimal Notation

x = 11.21110 \dots, x = - 3.21110 \dots

Solution steps

x^{2} - 8 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 36) = 413

x_{1, 2} = \frac{- ( - 8 ) \pm 4 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 13}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 4 13}{2 \cdot 1}

x = \frac{- ( - 8 ) + 4 13}{2 \cdot 1} : 2 (2 + 13)

x = \frac{- ( - 8 ) - 4 13}{2 \cdot 1} : 2 (2 - 13)

The solutions to the quadratic equation are:

x = 2 (2 + 13), x = 2 (2 - 13)

x, x^{2} + x y + y^{2} = C

(y - \frac{1}{2})^{2} = \frac{1}{4}

x^{2} = - 8 x - 12

5 x^{2} - 28 x + 15 = 0

2 (x + 2) (\frac{x}{2} - 1) = 0

What are the solutions to the equation x^2-8x-36=0 ?
The solutions to the equation x^2-8x-36=0 are x=2(2+sqrt(13)),x=2(2-sqrt(13))
Find the zeros of x^2-8x-36=0
The zeros of x^2-8x-36=0 are x=2(2+sqrt(13)),x=2(2-sqrt(13))